(3n-1)(2n^2+4n+4)=0

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Solution for (3n-1)(2n^2+4n+4)=0 equation:


Simplifying
(3n + -1)(2n2 + 4n + 4) = 0

Reorder the terms:
(-1 + 3n)(2n2 + 4n + 4) = 0

Reorder the terms:
(-1 + 3n)(4 + 4n + 2n2) = 0

Multiply (-1 + 3n) * (4 + 4n + 2n2)
(-1(4 + 4n + 2n2) + 3n * (4 + 4n + 2n2)) = 0
((4 * -1 + 4n * -1 + 2n2 * -1) + 3n * (4 + 4n + 2n2)) = 0
((-4 + -4n + -2n2) + 3n * (4 + 4n + 2n2)) = 0
(-4 + -4n + -2n2 + (4 * 3n + 4n * 3n + 2n2 * 3n)) = 0
(-4 + -4n + -2n2 + (12n + 12n2 + 6n3)) = 0

Reorder the terms:
(-4 + -4n + 12n + -2n2 + 12n2 + 6n3) = 0

Combine like terms: -4n + 12n = 8n
(-4 + 8n + -2n2 + 12n2 + 6n3) = 0

Combine like terms: -2n2 + 12n2 = 10n2
(-4 + 8n + 10n2 + 6n3) = 0

Solving
-4 + 8n + 10n2 + 6n3 = 0

Solving for variable 'n'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-2 + 4n + 5n2 + 3n3) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-2 + 4n + 5n2 + 3n3)' equal to zero and attempt to solve: Simplifying -2 + 4n + 5n2 + 3n3 = 0 Solving -2 + 4n + 5n2 + 3n3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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